## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson

# Chapter 8 - Polar Coordinates; Vectors - Section 8.4 Vectors - 8.4 Assess Your Understanding - Page 626: 28

#### Answer

$3i-5j$ and the position vector is: $(-3,-5)$

#### Work Step by Step

If a vector $v$ initiates at point $A(x_1,y_1)$ and terminates at $B(x_2,y_2)$, then $v =\lt x_2-x_1, y_2-y_1 \gt =(x_2-x_1)i+(y_2-y_1) \ j$ Here, we have: $A=(0,0)$ and $B=(-3,-5)$ Therefore, $v=(-3-0)i+(-5-0) \ j =-3i-5j$ and the position vector is: $(-3,-5)$

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