Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Chapter Test - Page 656: 18

Answer

horizontal, $5\sqrt 2$, vertical $-5\sqrt 2$

Work Step by Step

1. Based on the given points, we have $\vec v=\vec{P_1P_2}=(8\sqrt 2-3\sqrt 2)i+(2\sqrt 2-7\sqrt 2)j=5\sqrt 2i-5\sqrt 2j$ 2. Thus we have the horizontal component as $5\sqrt 2$ and vertical component as $-5\sqrt 2$
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