Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 8 - Polar Coordinates; Vectors - Chapter Test - Page 656: 14

Answer

$ 5 \sqrt 2i -5 \sqrt 2 \ j$

Work Step by Step

If a vector $v$ initiates at point $A(x_1,y_1)$ and terminates at $B(x_2,y_2)$, then $v =\lt x_2-x_1, y_2-y_1 \gt =(x_2-x_1)i+(y_2-y_1) \ j$ Here, we have: $A=(3\sqrt 2, 7 \sqrt 2)$ and $B=(8\sqrt 2, 2 \sqrt 2)$ Therefore, $v=(8\sqrt 2-3 \sqrt 2)i+(2\sqrt 2-7 \sqrt 2) \ j \\= 5 \sqrt 2i -5 \sqrt 2 \ j$
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