Answer
$\frac{3}{2}(cos297^\circ+i\ sin297^\circ)$
Work Step by Step
Use the given complex numbers, we have $\frac{w}{z}=\frac{3}{2}(cos(22^\circ-85^\circ)+i\ sin(22^\circ-85^\circ))=\frac{3}{2}(cos(-63^\circ)+i\ sin(-63^\circ))=\frac{3}{2}(cos(360-63)^\circ+i\ sin(360-63^\circ)=\frac{3}{2}(cos297^\circ+i\ sin297^\circ)$
