Answer
$\sin (\alpha-\beta)=\sin \alpha \cos \beta-\cos \alpha \sin \beta$
Work Step by Step
Recall the Difference formula for sine:
$\sin (\alpha-\beta)=\sin \alpha \cos \beta-\cos \alpha \sin \beta$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.5 Sum and Difference Formulas - 6.5 Assess Your Understanding - Page 508: 6
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