Answer
$0, \frac{5}{2}$
Work Step by Step
Treat $(2x-1)$ as a single unit,
$(2x-1)^2-3(2x-1)-4=0$,
$((2x-1)+1)((2x-1)-4)=0$,
$(2x)(2x-5)=0$,
$x=0, \frac{5}{2}$
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