Answer
$ \frac{\sqrt 2}{2},-\frac{1}{2}$
Work Step by Step
$sin(\frac{\pi}{4})=\frac{\sqrt 2}{2}$,
$cos(\frac{8\pi}{3})=cos(2\pi+\pi-\frac{\pi}{3})=-cos(\frac{\pi}{3})=-\frac{1}{2}$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 6 - Analytic Trigonometry - Section 6.3 Trigonometric Equations - 6.3 Assess Your Understanding - Page 487: 2
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