Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 6 - Analytic Trigonometry - Section 6.3 Trigonometric Equations - 6.3 Assess Your Understanding - Page 487: 4

Answer

$\frac{1\pm\sqrt {5}}{2}$

Work Step by Step

$x^2-x-1=0$, $x=\frac{1\pm\sqrt {1+4}}{2}=\frac{1\pm\sqrt {5}}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.