Answer
$\frac{1}{|u|}$
Work Step by Step
1. Let $sec^{-1}u=t, 0\lt t\lt\pi$, we have $sec(t)=u$.
2. Let $r=|u|,x=1$, we have $y=\sqrt {u^2-1}$
3. Thus $cos(sec^{-1}u)=cos(t)=\frac{x}{r}=\frac{1}{|u|}$
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.