Answer
$0,\pm\pi,\pm2\pi$.
Work Step by Step
$y=csc(x)=\frac{1}{sin(x)}$ has vertical asymptotes when $sin(x)=0 \Longrightarrow x=0,\pm\pi,\pm2\pi$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 5 - Trigonometric Functions - Section 5.5 Graphs of the Tangent, Cotangent, Cosecant, and Secant Functions - 5.5 Assess Your Understanding - Page 441: 14
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