Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.5 Graphs of the Tangent, Cotangent, Cosecant, and Secant Functions - 5.5 Assess Your Understanding - Page 441: 11

Answer

$x=0,\pm2\pi$. $x=\pm\pi$.

Work Step by Step

1. $y=sec(x)=\frac{1}{cos(x)}=1 \Longrightarrow cos(x)=1 \Longrightarrow x=0,\pm2\pi$. 2. $y=sec(x)=\frac{1}{cos(x)}=-1 \Longrightarrow cos(x)=-1 \Longrightarrow x=\pm\pi$.
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