Answer
$\pm\frac{\pi}{2},\pm\frac{3\pi}{2}$.
Work Step by Step
$y=sec(x)=\frac{1}{cos(x)}$ has vertical asymptotes when $cos(x)=0 \Longrightarrow x=\pm\frac{\pi}{2},\pm\frac{3\pi}{2}$.
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