Answer
$44-4\pi$ square units
Work Step by Step
$AE=AB=r=\frac{s}{\theta}=\frac{2\pi}{\pi/2}=4$
Area of the rectangle=$AB\times AD=4(7+4)=44$
Area of the sector=$\frac{1}{2}r^{2}\theta=\frac{1}{2}\times(4)^{2}\times\frac{\pi}{2}=4\pi$
$\text{Area of the portion outside the circle=
Area of the rectangle- Area of the sector}$
$=44-4\pi$ square units
