Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.1 Angles and Their Measures - 5.1 Assess Your Understanding - Page 388: 114

Answer

Linear speed $v=\frac{6\pi}{7}\text{ ft/s} \approx2.6928\text{ ft/s}$ Angular speed $\omega=\frac{\pi}{35}\text{ rad/s}\approx0.08976\text{ rad/s}$

Work Step by Step

Angular speed $\omega=\frac{\theta}{t}$ Using the formula above gives: $\omega=\frac{1\text{ revolution}}{70\text{ s}}$ $\omega=\frac{2\pi\text{ rad}}{70\text{ s}}\\$ $\omega=\frac{\pi}{35}\text{ rad/s}\\$ $\omega\approx0.08976\,rad/s$ Linear speed $v=r\omega$ so $v=30\text{ ft}\times\frac{\pi}{35}\text{ rad/s}$ $v=\frac{6\pi}{7}\text{ ft/s}\approx2.6928\,ft/s$
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