Answer
$\approx66,633.32\text{ mi/h}$
Work Step by Step
We have:
$r=9.29\times10^{7}\text{ mi}$
$\omega=\dfrac{1\text{ revolution}}{365\text{ day}}=\dfrac{1\text{ revolution}}{365\text{ days}}\times\dfrac{2\pi\text{ rad}}{1\text{ revolution}}\times\dfrac{1\text{ day}}{24\text{ h}}$
$\omega=\dfrac{\pi}{4380}\text{ rad/h}$
The formuala for linear speed $v$ is $v=r\omega$. Using this formula gives:
$v=9.29\times10^{7}\text{ mi}\times\dfrac{\pi}{4380}\text{ rad/h}$
$v\approx66633.32\text{ mi/h}$
