## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$9.425 \, m^2$
$\because A = \dfrac{1}{2}r^2 \theta$ where $r$: Radius of the circle $\theta$: Central angle that subtends the arc (in radians) $A$: Area of the sector of the circle formed by the central angle $\theta$ Convert $\theta$ from degrees to radians: $$\theta = 120 \times \dfrac{\pi}{180}= \dfrac{2 \pi}{3} \text{ radians}$$ Use the formula above to obtain: $A= \dfrac{1}{2}\times (3)^2 \times \dfrac{2 \pi}{3} \approx \boxed{9.425 \, m^2}$