Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$61^{\circ} 14^{'} 24^{"}$
RECALL: $1^{\circ} = 60^{'} \text{ and } 1^{'} = 60^{"}$ $$\begin{split} 61.24^{\circ} = 61^{\circ}+0.24^{\circ} \\ & = 61^{\circ}+0.24 \times (1^{\circ}) \\ & = 61^{\circ}+0.24 \times (60^{'}) \\ & = 61^{\circ}+14.4^{'} \\ & = 61^{\circ}+14^{'}+0.4^{'} \\ & = 61^{\circ}+14^{'}+0.4 \times (1)^{'} \\ & = 61^{\circ}+14^{'}+0.4 \times (60)^{"} \\ & = 61^{\circ}+14^{'} + 24^{"} \end{split}$$ Thus, $61.24^{\circ} = 61^{\circ} 14^{'} 24^{"}$