Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Section 5.1 Angles and Their Measures - 5.1 Assess Your Understanding - Page 386: 31

Answer

$18^{\circ} 15^{'} 18^{"}$

Work Step by Step

RECALL: $1^{\circ} = 60^{'} \text{ and } 1^{'} = 60^{"}$ \begin{equation} \begin{split} 18.255^{\circ}&=18^{\circ}+0.255^{\circ} \\ & = 18^{\circ}+0.255 \times (1^{\circ}) \\ & = 18^{\circ}+0.255 \times (60)^{'} \\ & = 18^{\circ} + 15.3^{'} \\ & = 18^{\circ}+15^{'}+0.3^{'} \\ & = 18^{\circ}+15^{'}+0.3 \times (1)^{'} \\ & = 18^{\circ}+15^{'}+0.3 \times (60)^{"} \\ & = 18^{\circ}+15^{'}+18^{"} \end{split} \end{equation} Thus, $18.255^{\circ}= 18^{\circ} 15^{'} 18^{"}$
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