Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Chapter Review - Review Exercises - Page 458: 40

Answer

$y=-7sin(\frac{\pi}{4}x)$

Work Step by Step

1. The given graph resembles to $y=-sin(x)$, with a general form $y=-A\ sin(\omega x)$, 2. We can find the amplitude$A=7$, period$=8$, phase shift$=0$. 3. We have $\frac{2\pi}{\omega}=8$, thus $\omega=\frac{\pi}{4}$ 4. Thus we have $y=-7sin(\frac{\pi}{4}x)$
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