Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Chapter Review - Review Exercises - Page 458: 12

Answer

$1$

Work Step by Step

We know that: $\sec x=\dfrac{1}{\cos (x)}$ Therefore, $( \sec 50^{\circ}) ( \cos 50^{\circ})=\dfrac{1}{\cos 50^{\circ}} \times \cos 50^{\circ}=1$
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