Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Chapter Review - Review Exercises - Page 458: 12



Work Step by Step

We know that: $\sec x=\dfrac{1}{\cos (x)}$ Therefore, $( \sec 50^{\circ}) ( \cos 50^{\circ})=\dfrac{1}{\cos 50^{\circ}} \times \cos 50^{\circ}=1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.