Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 5 - Trigonometric Functions - Chapter Review - Review Exercises - Page 458: 33



Work Step by Step

The general form for the function can be expressed as: $y=A\sin \ (\omega x)$ where $A$ represents the amplitude. The $\omega$ can be found from the period by the formula: $\omega=\dfrac{2\pi}{T}$ and the phase shift is $\dfrac{\phi}{\omega}$. This means that $\phi=\omega \times \ Phase \ Shift$ We have: $A=|1|=1$, $\omega=2$, Therefore, the period of the function can be computed as: $T=\dfrac{ 2 \pi}{\omega}=\dfrac{2 \pi}{2}=\pi$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.