## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$\pi$
The general form for the function can be expressed as: $y=A\sin \ (\omega x)$ where $A$ represents the amplitude. The $\omega$ can be found from the period by the formula: $\omega=\dfrac{2\pi}{T}$ and the phase shift is $\dfrac{\phi}{\omega}$. This means that $\phi=\omega \times \ Phase \ Shift$ We have: $A=|1|=1$, $\omega=2$, Therefore, the period of the function can be computed as: $T=\dfrac{ 2 \pi}{\omega}=\dfrac{2 \pi}{2}=\pi$