Answer
$(-\infty,0]\cup[1,\infty)$.
See graph.
Work Step by Step
Step 1. $x^2\ge x \Longrightarrow x(x-1)\ge0$, identify boundary points as $x=0,1$.
Step 2. Form intervals $(-\infty,0],[0,1],[1,\infty)$.
Step 3. Choose test values for each 1interval $x=-1,0.5,2$.
Step 4. Test the inequality to get results: $True,\ False,\ True$
Step 5. We have the solution $(-\infty,0]\cup[1,\infty)$.
Step 6. See graph.
