Answer
center $(-2,1)$, radius $r=3$.
See graph.
Work Step by Step
Step 1. $x^2+4x+y^2-2y-4=0 \Longrightarrow x^2+4x+4+y^2-2y+1=4+4+1 \Longrightarrow (x+2)^2+(y-1)^2=9$, thus we have the center $(-2,1)$, radius $r=3$.
Step 2. See graph.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 3 - Polynomial and Rational Functions - Cumulative Review - Page 270: 10
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