## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$(-9,9)$. Refer to the graph below.
Using the definition of the absolute value, we have $$|x|\lt 9\Longrightarrow -9\lt x\lt 9$$ and this can be written in terms of intervals as all $x$ in the interval $(-9,9)$. To graph the solution set, plot holes (or hollow dots) at $-9$ and $9$ then shade the region in between them. (Refer to the graph below)