## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$\bf{True}$.
The coordinates of the vertex of a quadratic function $f(x) = ax^2+bx+c$ are given by: $\displaystyle(\frac{-b}{2a}, f(-\frac{2}{a}))$ We see that the given quadratic function has the coefficients: $a=-1, b=4, c=5$. Therefore, the coordinates of the function's vertex can be expressed as: $(-\dfrac{4}{2\cdot(-1)}, f(-\dfrac{4}{2\cdot(-1)}))=(-\dfrac{4}{-2}, f(-(-2)) \\=[2, f(2)]$ So, the vertex has a y-coordinate of $f(2)$. Therefore, the given statement is $\bf{True}$.