Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Section 2.4 Properties of Quadratic Functions - 2.4 Assess Your Understanding - Page 157: 28

Answer

See graph.

Work Step by Step

To obtain the graph of $y=-2x^2+6x+2=-2(x-\frac{3}{2})^2+\frac{13}{2}$ from $y=x^2$, shift the curve $\frac{3}{2}$ unit(s) to the right, stretch vertically by a factor of 2, reflect across the x-axis, then shift $\frac{13}{2}$ unit(s) up. See graph.
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