Answer
$\bf{-\dfrac{b}{2a}}$.
Work Step by Step
The vertex of a quadratic function $ax^2+bx+c=0, a \ne 0$ has an $x$-coordinate of $-\dfrac{b}{2a}$.
Therefore, the missing term in the given statement is:
$\bf{-\dfrac{b}{2a}}$.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Section 2.4 Properties of Quadratic Functions - 2.4 Assess Your Understanding - Page 157: 7
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