Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 2 - Linear and Quadratic Functions - Cumulative Review - Page 188: 5

Answer

$y=-\frac{1}{2}x+\frac{13}{2}$ See graph.

Work Step by Step

Step 1. Identify the slope of the given line $y=2x+1$, we have $m_1=2$ Step 2. The slope of the line perpendicular to the above, is then $m=-\frac{1}{m_1}=-\frac{1}{2}$ Step 3. With point $(3,5)$, we have $y-5=-\frac{1}{2}(x-3)$ or $y=-\frac{1}{2}x+\frac{13}{2}$ Step 4. See graph.
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