Answer
$5\sqrt 2$, $(\frac{3}{2},\frac{1}{2})$
Work Step by Step
Step 1. Use the distance formula, we have $d_{PQ}=\sqrt {(-1-4)^2+(-2-3)^2}=5\sqrt 2$
Step 2. Use the midpoint formula, we have $x_m=\frac{-1+4}{2}=\frac{3}{2}$ and $y_m=\frac{3-2}{2}=\frac{1}{2}$, thus the midpoint is $(\frac{3}{2},\frac{1}{2})$
