Answer
maximum $f(3) =21$
Work Step by Step
Given $f(x)=-2x^2+12x+3$, we have $a=-2\lt0, b=12$, thus the function has a maximum at $x=-\frac{b}{2a}=-\frac{12}{2(-2)}=3$ and $f(3)=-2(3)^2+12(3)+3=21$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 2 - Linear and Quadratic Functions - Chapter Test - Page 188: 11
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