# Chapter 12 - Counting and Probability - Section 12.3 Probability - 12.3 Assess Your Understanding - Page 885: 46

$0.1$

#### Work Step by Step

The Addition Rule of Probabilities says that: $P(A\cup B)=P(A)+P(B)-P(A\cap B)$. If A and B are mutually exclusive, then $P(A\cap B)=0$. Solve for $P(A\cap B)$ in the formula above to obtain: $P(A\cup B)=P(A)+P(B)-P(A\cap B)\\ P(A\cap B)=P(A)+P(B)-P(A\cup B)\\$ Substitute the given values then solve for $P(A\cap B)$ to obtain: $P(A\cap B)=0.25+0.46-0.6=0.1$

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