Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Section 12.3 Probability - 12.3 Assess Your Understanding - Page 885: 29

Answer

$P(2)=P(4)=P(6)=\dfrac{1}{9}$; $P(1)=P(3)=P(5)=\dfrac{2}{9}.$

Work Step by Step

If $P(2)=P(4)=P(6)=x$, then $P(1)=P(3)=P(5)=2x.$ We know that: $P(1)+P(2)+P(3)+P(4)+P(5)+P(6)=1\\2x+x+2x+x+2x+x=1\\9x=1\\x=\dfrac{1}{9}$ Thus, $P(2)=P(4)=P(6)=\dfrac{1}{9}$, and $P(1)=P(3)=P(5)=\dfrac{2}{9}.$
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