## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$P(2)=P(4)=P(1)=P(3)=P(5)=0.2=\dfrac{1}{5}$
$P(2)=P(4)=P(6)=P(1)=P(3)=P(5)=x.$ and $P(6)=0.$ We know that $P(1)+P(2)+P(3)+P(4)+P(5)+P(6)=1\\x+x+x+x+x+0=1\\5x=1\\x=0.2$ Thus, $P(2)=P(4)=P(1)=P(3)=P(5)=0.2=\dfrac{1}{5}$