Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 12 - Counting and Probability - Cumulative Review - Page 890: 1

Answer

$ \frac{1\pm\sqrt {2}i}{3}$

Work Step by Step

$3x^2-2x+1=0$, $x=\frac{2\pm\sqrt {4-4(3)(1)}}{2(3)}=\frac{1\pm\sqrt {2}i}{3}$
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