Answer
$0.1608$
Work Step by Step
For each roll, the probability of getting a 4 is $p=\frac{1}{6}$, with $n=5, x=2$, use binomial formula, we have $P(2)=\ _5C_2\ p^2(1-p)^3=10(\frac{1}{6})^2(\frac{5}{6})^3\approx0.1608$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 12 - Counting and Probability - Chapter Test - Page 889: 16
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