Answer
$56$
Work Step by Step
If we want to choose $k$ elements out of $n$ regarding the order and not allowing repetition, we can do this with permutations.
The permutation formula is:
$P(n,k)=\frac{n!}{(n-k)!}$ ways
Here, the order matters and so we use permutations:
$\require{cancel}P(8,2)=\frac{8!}{(8-2)!}=\frac{8\cdot7\cdot6!}{6!}=\frac{8\cdot7\cdot\cancel{6!}}{\cancel{6!}}=8\cdot7=56$
