Answer
$\frac{8}{3}$
Work Step by Step
$log_2(3x-2)+log_2x=4$,
$log_2(3x^2-2x)=4$,
$3x^2-2x=2^4$,
$3x^2-2x-16=0$,
$(x+2)(3x-8)=0$,
thus $x=-2, \frac{8}{3}$,
check, only $x= \frac{8}{3}$ fits.
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Chapter 12 - Counting and Probability - Cumulative Review - Page 890: 8
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