Answer
$301$.
Work Step by Step
The nth term of an arithmetic sequence is given by:
$a_n=a_1+(n-1) d \\ 41=2+3(n-1) \\ 39 =3(n-1) \\ n=14$
We see that there is a constant difference between the terms of $d=4$ and the terms are part of an arithmetic sequence.
The terms of the sum are the first $14$ terms of the arithmetic sequence, starting with $a_{1}=2$ and with a difference of $d= 3$
The sum of the sequence is thus:
$S_{n}= \dfrac{n}{2}\left(a_{1}+a_{n}\right)$
Now, $S_{14}= \dfrac{14}{2}[2+41] \\=(7)(43) \\=301$
Therefore, the sum of the sequence is: $301$.
