Answer
We cannot apply Cramer's rule.
Work Step by Step
Cramer's rule states that
$a x+b y=p \\ cx+dy=q$
$\triangle=\left|\begin{array}{ll}{a}&{b}\\{c}&{d}\end{array}\right|, \triangle_{1}=\left|\begin{array}{ll}{p}&{b}\\{q}&{d}\end{array}\right|, \triangle_{2}=\left|\begin{array}{ll}{a}&{p}\\{c}&{q}\end{array}\right|$; $ x=\dfrac{\triangle_1}{\triangle}; y=\dfrac{\triangle_2}{\triangle} (D\displaystyle \neq 0)$
From the given system of equations, we have:
$ \left[\begin{array}{ll}a & b\\c & d \end{array}\right]=\left[\begin{array}{ll}
3 & -2\\ 6 & 4\end{array}\right],\quad \left[\begin{array}{l}
p\\q \end{array}\right]=\left[\begin{array}{l}4\\0\end{array}\right]$
But $\triangle = \left|\begin{array}{ll}
3 & -2\\ 6 & 4 \end{array}\right|=12-12=0$
We see that determinant of the given system is $0$. So, we cannot apply Cramer's rule to find the values of $x$ and $y$.