Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 10 - Systems of Equations and Inequalities - Section 10.1 Systems of Linear Equations: Substitution and Elimination - 10.1 Assess Your Understanding - Page 735: 56

Answer

$\text{Length = 775 meters and Width = 725 meters}$

Work Step by Step

Let us consider that $x$=width (in meters) and $y$=length ( in meters). We are given: $y-x=50~~~(1) $ and the perimeter is: $2x+2y=3000~~~(2)$ Re-write equation (1) as: $y=x+50 ~~~(3)$ Plug equation (3) into equation (2) to solve for $x$; then we get: $2x+(2)(x+50)=3000 \\ 2x+2x+100=3000 \implies x=725$ Now, back substitute the value of $x$ into Equation (3) to solve for $y$: $y=725+50 \implies y=775$ Therefore, the dimensions of the field are: $\text{Length = 775 meters and Width = 725 meters}$
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