Answer
$(x,y)=(\dfrac{11}{5},\dfrac{-3}{5})$
Work Step by Step
$ y=2x-5 ~~~ (1)$
$x=3y+4 ~~~(2)$
Substitute $y=2x-5$ into Equation-2 to evaluate the value of $x$.
$x=3(2x-5)+4 \\ 5x=11 \implies x=\dfrac{11}{5}$
Plug $x=\dfrac{11}{5}$ back into one of the equations and solve for y.
Thus, $y=(2)(\dfrac{11}{5})-5 \\ y=\dfrac{-3}{5}$
Therefore, $(x,y)=(\dfrac{11}{5},\dfrac{-3}{5})$
