Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Chapter 1 - Functions and Their Graphs - Chapter Review - Review Exercises - Page 113: 15

Answer

$-4x-2h+1$

Work Step by Step

We find the difference quotient as follows: $\displaystyle \frac{f(x+h)-f(x)}{h} =\frac{-2(x+h)^2+(x+h)+1-(-2x^2+x+1)}{h} \\=\dfrac{-2(x^2+h^2+2h)+(x+h)+1-(-2x^2+x+1)}{h} \\=\dfrac{-2x^2-4xh-2h^2+x+h+1+2x^2-x-1}{h} \\=\dfrac{-4xh-2h^2+h}{h} \\=-4x-2h+1$
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