Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 85

Answer

$ x^3-6x^2+12x-8$

Work Step by Step

We cube (expand) the binomial as follows: $$ (x - 2)^3=(x-2)(x-2)(x-2)=x^3+3x(-2)^2+3(-2)x^2+(-2)^3\\ = x^3-6x^2+12x-8 .$$
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