Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 39

Answer

$ 15y^2 - 27y + 30$

Work Step by Step

We simplify by removing the parentheses and then combine the like terms as follows $$ 9(y^2 - 3y + 4) - 6(1 - y^2)=9y^2 - 27y + 36 - 6 +6y^2\\ = 15y^2 - 27y + 30 .$$
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