Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.3 Polynomials - A.3 Assess Your Understanding - Page A31: 103


quotient$=x^2+ax+a^2$, remainder$=0$

Work Step by Step

1. Use the cube formula, we have $x^3-a^3=(x-a)(x^2+ax+a^2)$, thus we have the quotient$=x^2+ax+a^2$, remainder$=0$ 2. We have $(x^2+ax+a^2)(x-a)+(0)=x^3-a^3$
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