Answer
quotient$=x^2+ax+a^2$, remainder$=0$
Work Step by Step
1. Use the cube formula, we have $x^3-a^3=(x-a)(x^2+ax+a^2)$, thus we have the quotient$=x^2+ax+a^2$, remainder$=0$
2. We have $(x^2+ax+a^2)(x-a)+(0)=x^3-a^3$
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