Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 135

Answer

$V=\frac{4}{3} \pi r^3$

Work Step by Step

Since the volume $V$ of a sphere is $\frac{4}{3}$ times $\pi$ times the cube of the radius $r$, then we have $$ V=\frac{4}{3} \pi r^3 .$$
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