Work Step by Step
Let $x=2$. Then by substitution, we have $$ 2x^3-3x^2+5x-4=2(2)^3-3(2)^2+5(2)-4\\=16-12+10-4=10 .$$ When $x=1$, we have $$ 2x^3-3x^2+5x-4=2(1)^3-3(1)^2+5(1)-4\\=2-3+5-4=0 .$$
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