Answer
$10,0$
Work Step by Step
Let $x=2$. Then by substitution, we have
$$
2x^3-3x^2+5x-4=2(2)^3-3(2)^2+5(2)-4\\=16-12+10-4=10
.$$
When $x=1$, we have
$$
2x^3-3x^2+5x-4=2(1)^3-3(1)^2+5(1)-4\\=2-3+5-4=0
.$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 117
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