Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

Published by Pearson
ISBN 10: 0-32193-104-1
ISBN 13: 978-0-32193-104-7

Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 118


$8, 44$

Work Step by Step

Let $x=1$. Then by substitution, we have $$ 4x^3+3x^2-x+2=4(1)^3+3(1)^2-(1)+2\\=4+3-1+2=8 .$$ When $x=2$, we have $$ 4x^3+3x^2-x+2=4(2)^3+3(2)^2-(2)+2\\=32+12-2+2=44 .$$
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