Answer
$8, 44$
Work Step by Step
Let $x=1$. Then by substitution, we have
$$
4x^3+3x^2-x+2=4(1)^3+3(1)^2-(1)+2\\=4+3-1+2=8
.$$
When $x=2$, we have
$$
4x^3+3x^2-x+2=4(2)^3+3(2)^2-(2)+2\\=32+12-2+2=44
.$$
Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)
by Sullivan III, Michael
Published by
Pearson
ISBN 10:
0-32193-104-1
ISBN 13:
978-0-32193-104-7
Appendix A - Review - A.1 Algebra Essentials - A.1 Assess Your Understanding - Page A12: 118
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
