## Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry (3rd Edition)

$8, 44$
Let $x=1$. Then by substitution, we have $$4x^3+3x^2-x+2=4(1)^3+3(1)^2-(1)+2\\=4+3-1+2=8 .$$ When $x=2$, we have $$4x^3+3x^2-x+2=4(2)^3+3(2)^2-(2)+2\\=32+12-2+2=44 .$$