Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises: 95

Answer

$$11y^{3}-18y^{2}-4y$$

Work Step by Step

Initial Equation: $-y(y^{2}-4)+6y^{2}(2y-3)$ Distribute the $-y$ and $6y^{2}$ to their respective parenthesis: $$-y^{3}-4y+12y^{3}-18y^{2}$$ Then, combine like terms to arrive at final answer: $$11y^{3}-18y^{2}-4y$$
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