Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.3 Polynomials - R.3 Exercises: 90

Answer

$$9p^{2}+30p+25$$

Work Step by Step

Initial equation: $$(3p+5)^{2}$$ The expression can be rewritten by expanding it to two set of parenthesis like so: $$(3p+5)(3p+5)$$ After expansion, it is a matter of simple distribution of terms in the first set of parenthesis to the second. The $3p$ in the first parenthesis will be multiplied by the two terms in the second, and the $5$ will be as well. Doing this gives you: $$9p^{2}+15p+15p+25$$ All that is left is to combine like terms to arrive at the final answer: $$9p^{2}+30p+25$$
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